# Line slope calculator 6x+2y=32

**Straight line given by points A[2; 10] and B[4; 4]**

## Calculation:

**Slope-intercept form of line:**y = -3x+16

**Canonical form of the line equation:**6x+2y-32 = 0

**Parametric form of the line equation:**

x = 2t+2

y = -6t+10 ; t ∈ R

**Slope:**m = -3

**Slope angle of line: φ =**-71°33'54″ = -1.249 rad

**X intercept:**x

_{0}= 5.3333

**Y intercept:**y

_{0}= q = 16

**Distance line from the origin:**d

_{0}= 5.0596

**The length of the segment AB: |AB| =**6.3246

**Vector: AB =**(2; -6)

**Normal vector: n =**(6; 2)

**Midpoint of the segment AB: M =**[3; 7]

**Perpendicular Bisector equation:**2x-6y+36 = 0

**Vector OA = (2; 10) ; |OA| = 10.198**

**Vector OB = (4; 4) ; |OB| = 5.6569**

**Scalar product OA .OB = 48**

**Angle ∠ AOB = 33°41'24″ = 0.588 rad**